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2x^2+35x-6.9=0
a = 2; b = 35; c = -6.9;
Δ = b2-4ac
Δ = 352-4·2·(-6.9)
Δ = 1280.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-\sqrt{1280.2}}{2*2}=\frac{-35-\sqrt{1280.2}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+\sqrt{1280.2}}{2*2}=\frac{-35+\sqrt{1280.2}}{4} $
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